# Equation

John Pistrell
Visitor
2015-11-30 04:50:43
#1
How to solve this?
z(z2 + z + 1)(z2 + 25) = 0

## RE: Equation

Popoviciu
Visitor
2015-12-04 04:18:16
#2
Here you can split your equation in three equations. There we have a product which is equal with 0. So though, every factor of this product could be zero.
So though,

Sol. 1. z = 0 ..
And this is one of the solutions.
Sol. 2. z2 + z+ 1 = 0
This is a two degree equation. So, we have to find out the Discriminant,
Δ = 1 - 4 = -3 < 0 => the equation doesn't have real solutions

Sol. 3. z2 + 25 = 0
The same as above. This is a two degree equation. So, we have to find out the Discriminant,
Δ = 0 - 25 = -25 < 0 => the equation doesn't have real solutions

Finally, the entire equation has only one solution: 0

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