# Inequality

## (a+b)(b+c)(c+a) ≥ 8abc

**For any ***a*, *b* and *c* **≥** 0 we have

**(a + b)(b + c)(c + a) ≥ 8abc**

**Proof. **We have

We add 4*ab * to this

And now we have the same thing here

*a*, *b* and *c* are non-negative numbers.

So, we can multiply these 3 inequalities:

**Keywords: **
Algebraic Inequalities, algebra, inequality

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